Base | Representation |
---|---|
bin | 1011111011101100010001… |
… | …0110011010110010011011 |
3 | 1201110021100000121220212200 |
4 | 2332323010112122302123 |
5 | 3204430003312130321 |
6 | 43523145113541243 |
7 | 2522616624523320 |
oct | 276730426326233 |
9 | 51407300556780 |
10 | 13120124333211 |
11 | 41a9239166235 |
12 | 157a927114823 |
13 | 7422b7855b1c |
14 | 335035a94b47 |
15 | 17b4404ebd26 |
hex | beec459ac9b |
13120124333211 has 48 divisors (see below), whose sum is σ = 21759497760000. Its totient is φ = 7462312951104.
The previous prime is 13120124333209. The next prime is 13120124333219. The reversal of 13120124333211 is 11233342102131.
13120124333211 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 0 + 12 + 433 + 3 + 211 = 666.
It is not a de Polignac number, because 13120124333211 - 21 = 13120124333209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13120124333219) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 50350120 + ... + 50610026.
It is an arithmetic number, because the mean of its divisors is an integer number (453322870000).
Almost surely, 213120124333211 is an apocalyptic number.
13120124333211 is a deficient number, since it is larger than the sum of its proper divisors (8639373426789).
13120124333211 is a wasteful number, since it uses less digits than its factorization.
13120124333211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263648 (or 263645 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 13120124333211 its reverse (11233342102131), we get a palindrome (24353466435342).
The spelling of 13120124333211 in words is "thirteen trillion, one hundred twenty billion, one hundred twenty-four million, three hundred thirty-three thousand, two hundred eleven".
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