Base | Representation |
---|---|
bin | 1011111011101100010011… |
… | …0001000000001110110011 |
3 | 1201110021100111201222200221 |
4 | 2332323010301000032303 |
5 | 3204430012103133243 |
6 | 43523145523153511 |
7 | 2522620041000403 |
oct | 276730461001663 |
9 | 51407314658627 |
10 | 13120131302323 |
11 | 41a9242096231 |
12 | 157a929515897 |
13 | 7422b9125c66 |
14 | 33503698a803 |
15 | 17b440e26bed |
hex | beec4c403b3 |
13120131302323 has 2 divisors, whose sum is σ = 13120131302324. Its totient is φ = 13120131302322.
The previous prime is 13120131302263. The next prime is 13120131302347. The reversal of 13120131302323 is 32320313102131.
13120131302323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13120131302323 - 221 = 13120129205171 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120131302393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560065651161 + 6560065651162.
It is an arithmetic number, because the mean of its divisors is an integer number (6560065651162).
Almost surely, 213120131302323 is an apocalyptic number.
13120131302323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120131302323 is an equidigital number, since it uses as much as digits as its factorization.
13120131302323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13120131302323 its reverse (32320313102131), we get a palindrome (45440444404454).
The spelling of 13120131302323 in words is "thirteen trillion, one hundred twenty billion, one hundred thirty-one million, three hundred two thousand, three hundred twenty-three".
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