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131201321434481 is a prime number
BaseRepresentation
bin11101110101001110110000…
…001010000111110101110001
3122012112201112200020020002002
4131311032300022013311301
5114144100301241400411
61143013015513303345
736430661024340254
oct3565166012076561
9565481480206062
10131201321434481
11388941935a1631
121286b841104b55
13582930187118c
14245826bdc709b
151027caa2aa33b
hex7753b0287d71

131201321434481 has 2 divisors, whose sum is σ = 131201321434482. Its totient is φ = 131201321434480.

The previous prime is 131201321434397. The next prime is 131201321434499. The reversal of 131201321434481 is 184434123102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88172851201600 + 43028470232881 = 9390040^2 + 6559609^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131201321434481 is a prime.

It is a super-2 number, since 2×1312013214344812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131201321034481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600660717240 + 65600660717241.

It is an arithmetic number, because the mean of its divisors is an integer number (65600660717241).

Almost surely, 2131201321434481 is an apocalyptic number.

It is an amenable number.

131201321434481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201321434481 is an equidigital number, since it uses as much as digits as its factorization.

131201321434481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 38.

The spelling of 131201321434481 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred twenty-one million, four hundred thirty-four thousand, four hundred eighty-one".