Base | Representation |
---|---|
bin | 1011111011101100010101… |
… | …0011101101101010111011 |
3 | 1201110021101010212021012112 |
4 | 2332323011103231222323 |
5 | 3204430021420320324 |
6 | 43523150450202535 |
7 | 2522620211225216 |
oct | 276730523555273 |
9 | 51407333767175 |
10 | 13120140401339 |
11 | 41a9247240484 |
12 | 157a93058344b |
13 | 7422bac906aa |
14 | 335037c7877d |
15 | 17b441b22c0e |
hex | beec54edabb |
13120140401339 has 2 divisors, whose sum is σ = 13120140401340. Its totient is φ = 13120140401338.
The previous prime is 13120140401309. The next prime is 13120140401353. The reversal of 13120140401339 is 93310404102131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13120140401339 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120140401309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560070200669 + 6560070200670.
It is an arithmetic number, because the mean of its divisors is an integer number (6560070200670).
Almost surely, 213120140401339 is an apocalyptic number.
13120140401339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120140401339 is an equidigital number, since it uses as much as digits as its factorization.
13120140401339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 13120140401339 in words is "thirteen trillion, one hundred twenty billion, one hundred forty million, four hundred one thousand, three hundred thirty-nine".
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