Base | Representation |
---|---|
bin | 11101110101001110110101… |
… | …011100100000100000111110 |
3 | 122012112201202212010221110220 |
4 | 131311032311130200200332 |
5 | 114144100441443441342 |
6 | 1143013032402442210 |
7 | 36430663152332502 |
oct | 3565166534404076 |
9 | 565481685127426 |
10 | 131201410140222 |
11 | 38894229679564 |
12 | 1286b866963366 |
13 | 582931705bc96 |
14 | 2458279ab8302 |
15 | 1027cb2e7d5ec |
hex | 7753b572083e |
131201410140222 has 16 divisors (see below), whose sum is σ = 262404714540672. Its totient is φ = 43733487670040.
The previous prime is 131201410140221. The next prime is 131201410140263. The reversal of 131201410140222 is 222041014102131.
It is a junction number, because it is equal to n+sod(n) for n = 131201410140192 and 131201410140201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131201410140221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78026304 + ... + 79690067.
It is an arithmetic number, because the mean of its divisors is an integer number (16400294658792).
Almost surely, 2131201410140222 is an apocalyptic number.
131201410140222 is an abundant number, since it is smaller than the sum of its proper divisors (131203304400450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131201410140222 is a wasteful number, since it uses less digits than its factorization.
131201410140222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157855023.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 131201410140222 its reverse (222041014102131), we get a palindrome (353242424242353).
The spelling of 131201410140222 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred ten million, one hundred forty thousand, two hundred twenty-two".
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