131201410200433 has 4 divisors (see below), whose sum is σ = 131201643211380. Its totient is φ = 131201177189488.

The previous prime is 131201410200361. The next prime is 131201410200437. The reversal of 131201410200433 is 334002014102131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 120441120837489 + 10760289362944 = 10974567^2 + 3280288^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201410200433 - 2¹⁷ = 131201410069361 is a prime.

It is a super-2 number, since 2×131201410200433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131201410200398 and 131201410200407.

It is not an unprimeable number, because it can be changed into a prime (131201410200437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115658818 + ... + 116787691.

It is an arithmetic number, because the mean of its divisors is an integer number (32800410802845).

Almost surely, 2^{131201410200433} is an apocalyptic number.

It is an amenable number.

131201410200433 is a deficient number, since it is larger than the sum of its proper divisors (233010947).

131201410200433 is an equidigital number, since it uses as much as digits as its factorization.

131201410200433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 233010946.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131201410200433 its reverse (334002014102131), we get a palindrome (465203424302564).

The spelling of 131201410200433 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred ten million, two hundred thousand, four hundred thirty-three".