Base | Representation |
---|---|
bin | 11101110101001110110101… |
… | …011100101111100110111010 |
3 | 122012112201202212021002021112 |
4 | 131311032311130233212322 |
5 | 114144100442002431132 |
6 | 1143013032404040322 |
7 | 36430663153010645 |
oct | 3565166534574672 |
9 | 565481685232245 |
10 | 131201410202042 |
11 | 38894229710a54 |
12 | 1286b8669930a2 |
13 | 582931708116b |
14 | 2458279ad2a5c |
15 | 1027cb2e91ab2 |
hex | 7753b572f9ba |
131201410202042 has 16 divisors (see below), whose sum is σ = 201388998924960. Its totient is φ = 64071896776272.
The previous prime is 131201410202033. The next prime is 131201410202053. The reversal of 131201410202042 is 240202014102131.
It is a junction number, because it is equal to n+sod(n) for n = 131201410201999 and 131201410202017.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36493817 + ... + 39927452.
It is an arithmetic number, because the mean of its divisors is an integer number (12586812432810).
Almost surely, 2131201410202042 is an apocalyptic number.
131201410202042 is a deficient number, since it is larger than the sum of its proper divisors (70187588722918).
131201410202042 is a wasteful number, since it uses less digits than its factorization.
131201410202042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76441277.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 131201410202042 its reverse (240202014102131), we get a palindrome (371403424304173).
The spelling of 131201410202042 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred ten million, two hundred two thousand, forty-two".
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