Base | Representation |
---|---|
bin | 1011111011101100010101… |
… | …0111001011100100101011 |
3 | 1201110021101012120102222221 |
4 | 2332323011113023210223 |
5 | 3204430022133412001 |
6 | 43523150521454511 |
7 | 2522620222032133 |
oct | 276730527134453 |
9 | 51407335512887 |
10 | 13120141310251 |
11 | 41a9247801348 |
12 | 157a930941437 |
13 | 7422bb21b301 |
14 | 335038033ac3 |
15 | 17b441c521a1 |
hex | beec55cb92b |
13120141310251 has 2 divisors, whose sum is σ = 13120141310252. Its totient is φ = 13120141310250.
The previous prime is 13120141310239. The next prime is 13120141310273. The reversal of 13120141310251 is 15201314102131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13120141310251 - 27 = 13120141310123 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120141310281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560070655125 + 6560070655126.
It is an arithmetic number, because the mean of its divisors is an integer number (6560070655126).
Almost surely, 213120141310251 is an apocalyptic number.
13120141310251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120141310251 is an equidigital number, since it uses as much as digits as its factorization.
13120141310251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13120141310251 its reverse (15201314102131), we get a palindrome (28321455412382).
The spelling of 13120141310251 in words is "thirteen trillion, one hundred twenty billion, one hundred forty-one million, three hundred ten thousand, two hundred fifty-one".
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