Base | Representation |
---|---|
bin | 1011111011101100101011… |
… | …0010011011111011010001 |
3 | 1201110021121112212021222121 |
4 | 2332323022302123323101 |
5 | 3204430213434404301 |
6 | 43523203532534241 |
7 | 2522622405550366 |
oct | 276731262337321 |
9 | 51407545767877 |
10 | 13120232341201 |
11 | 41a9294127237 |
12 | 157a957321381 |
13 | 74230404158b |
14 | 33504616c46d |
15 | 17b449c343a1 |
hex | beecac9bed1 |
13120232341201 has 8 divisors (see below), whose sum is σ = 13699501384320. Its totient is φ = 12549419780688.
The previous prime is 13120232341193. The next prime is 13120232341283. The reversal of 13120232341201 is 10214323202131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13120232341201 - 23 = 13120232341193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13120232344201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2114117481 + ... + 2114123686.
It is an arithmetic number, because the mean of its divisors is an integer number (1712437673040).
Almost surely, 213120232341201 is an apocalyptic number.
It is an amenable number.
13120232341201 is a deficient number, since it is larger than the sum of its proper divisors (579269043119).
13120232341201 is a wasteful number, since it uses less digits than its factorization.
13120232341201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4228241303.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13120232341201 its reverse (10214323202131), we get a palindrome (23334555543332).
The spelling of 13120232341201 in words is "thirteen trillion, one hundred twenty billion, two hundred thirty-two million, three hundred forty-one thousand, two hundred one".
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