Base | Representation |
---|---|
bin | 1011111011101101010100… |
… | …0010110011010000101011 |
3 | 1201110022001112121221201211 |
4 | 2332323111002303100223 |
5 | 3204431042011400433 |
6 | 43523233000453551 |
7 | 2522626565215114 |
oct | 276732502632053 |
9 | 51408045557654 |
10 | 13120404403243 |
11 | 41a9372267a75 |
12 | 157a9a4a7a2b7 |
13 | 742330896337 |
14 | 335060d5b20b |
15 | 17b459dc08cd |
hex | beed50b342b |
13120404403243 has 2 divisors, whose sum is σ = 13120404403244. Its totient is φ = 13120404403242.
The previous prime is 13120404403237. The next prime is 13120404403273. The reversal of 13120404403243 is 34230440402131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13120404403243 - 213 = 13120404395051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120404403273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560202201621 + 6560202201622.
It is an arithmetic number, because the mean of its divisors is an integer number (6560202201622).
Almost surely, 213120404403243 is an apocalyptic number.
13120404403243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120404403243 is an equidigital number, since it uses as much as digits as its factorization.
13120404403243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13120404403243 its reverse (34230440402131), we get a palindrome (47350844805374).
The spelling of 13120404403243 in words is "thirteen trillion, one hundred twenty billion, four hundred four million, four hundred three thousand, two hundred forty-three".
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