Base | Representation |
---|---|
bin | 1011111011101101011000… |
… | …0010001111100101100111 |
3 | 1201110022002200220220022111 |
4 | 2332323112002033211213 |
5 | 3204431110241044333 |
6 | 43523234353141451 |
7 | 2522630156453230 |
oct | 276732602174547 |
9 | 51408080826274 |
10 | 13120421034343 |
11 | 41a9380697187 |
12 | 157a9aa55a887 |
13 | 74233416a21c |
14 | 33506324a087 |
15 | 17b45b5a84cd |
hex | beed608f967 |
13120421034343 has 32 divisors (see below), whose sum is σ = 15359220817920. Its totient is φ = 10975993620480.
The previous prime is 13120421034311. The next prime is 13120421034359. The reversal of 13120421034343 is 34343012402131.
It is not a de Polignac number, because 13120421034343 - 25 = 13120421034311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120421044343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 407969898 + ... + 408002056.
It is an arithmetic number, because the mean of its divisors is an integer number (479975650560).
Almost surely, 213120421034343 is an apocalyptic number.
13120421034343 is a deficient number, since it is larger than the sum of its proper divisors (2238799783577).
13120421034343 is an equidigital number, since it uses as much as digits as its factorization.
13120421034343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40567.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13120421034343 its reverse (34343012402131), we get a palindrome (47463433436474).
The spelling of 13120421034343 in words is "thirteen trillion, one hundred twenty billion, four hundred twenty-one million, thirty-four thousand, three hundred forty-three".
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