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1312042657 = 1744975193
BaseRepresentation
bin100111000110100…
…0010111010100001
310101102211200011111
41032031002322201
510141340331112
6334105343321
744341115152
oct11615027241
93342750144
101312042657
11613683082
12307497b41
1317ba93503
14c6377929
157a2bd5a7
hex4e342ea1

1312042657 has 4 divisors (see below), whose sum is σ = 1312135300. Its totient is φ = 1311950016.

The previous prime is 1312042637. The next prime is 1312042687. The reversal of 1312042657 is 7562402131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1033686801 + 278355856 = 32151^2 + 16684^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312042657 - 215 = 1312009889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312042637) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20148 + ... + 55045.

It is an arithmetic number, because the mean of its divisors is an integer number (328033825).

Almost surely, 21312042657 is an apocalyptic number.

It is an amenable number.

1312042657 is a deficient number, since it is larger than the sum of its proper divisors (92643).

1312042657 is an equidigital number, since it uses as much as digits as its factorization.

1312042657 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 92642.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 1312042657 is about 36222.1293824645. The cubic root of 1312042657 is about 1094.7525992507.

Adding to 1312042657 its reverse (7562402131), we get a palindrome (8874444788).

The spelling of 1312042657 in words is "one billion, three hundred twelve million, forty-two thousand, six hundred fifty-seven".

Divisors: 1 17449 75193 1312042657