1312043313001 has 2 divisors, whose sum is σ = 1312043313002. Its totient is φ = 1312043313000.

The previous prime is 1312043312893. The next prime is 1312043313011. The reversal of 1312043313001 is 1003133402131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1280742626601 + 31300686400 = 1131699^2 + 176920^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312043313001 - 2¹¹ = 1312043310953 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312043313011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656021656500 + 656021656501.

It is an arithmetic number, because the mean of its divisors is an integer number (656021656501).

Almost surely, 2^{1312043313001} is an apocalyptic number.

It is an amenable number.

1312043313001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312043313001 is an equidigital number, since it uses as much as digits as its factorization.

1312043313001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1312043313001 its reverse (1003133402131), we get a palindrome (2315176715132).

The spelling of 1312043313001 in words is "one trillion, three hundred twelve billion, forty-three million, three hundred thirteen thousand, one".