Base | Representation |
---|---|
bin | 1011111011101101011101… |
… | …0011011010101010111011 |
3 | 1201110022011011221222200211 |
4 | 2332323113103122222323 |
5 | 3204431131213012103 |
6 | 43523240433211551 |
7 | 2522630535360265 |
oct | 276732723325273 |
9 | 51408134858624 |
10 | 13120442313403 |
11 | 41a9391700487 |
12 | 157a9b5700bb7 |
13 | 7423386aa899 |
14 | 335065dc8b35 |
15 | 17b45d3ad36d |
hex | beed74daabb |
13120442313403 has 2 divisors, whose sum is σ = 13120442313404. Its totient is φ = 13120442313402.
The previous prime is 13120442313353. The next prime is 13120442313443. The reversal of 13120442313403 is 30431324402131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13120442313403 - 229 = 13119905442491 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120442313443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560221156701 + 6560221156702.
It is an arithmetic number, because the mean of its divisors is an integer number (6560221156702).
Almost surely, 213120442313403 is an apocalyptic number.
13120442313403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120442313403 is an equidigital number, since it uses as much as digits as its factorization.
13120442313403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13120442313403 its reverse (30431324402131), we get a palindrome (43551766715534).
The spelling of 13120442313403 in words is "thirteen trillion, one hundred twenty billion, four hundred forty-two million, three hundred thirteen thousand, four hundred three".
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