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13120442553121 = 19690549608059
BaseRepresentation
bin1011111011101101011101…
…0100010101001100100001
31201110022011012102011112021
42332323113110111030201
53204431131243144441
643523240442301441
72522630540406211
oct276732724251441
951408135364467
1013120442553121
1141a93918545a2
12157a9b57b7881
13742338762a27
1433506604c241
1517b45d4093d1
hexbeed7515321

13120442553121 has 4 divisors (see below), whose sum is σ = 13810992161200. Its totient is φ = 12429892945044.

The previous prime is 13120442553059. The next prime is 13120442553133. The reversal of 13120442553121 is 12135524402131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13120442553121 - 27 = 13120442552993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13120442553521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345274804011 + ... + 345274804048.

It is an arithmetic number, because the mean of its divisors is an integer number (3452748040300).

Almost surely, 213120442553121 is an apocalyptic number.

It is an amenable number.

13120442553121 is a deficient number, since it is larger than the sum of its proper divisors (690549608079).

13120442553121 is an equidigital number, since it uses as much as digits as its factorization.

13120442553121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 690549608078.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 13120442553121 its reverse (12135524402131), we get a palindrome (25255966955252).

The spelling of 13120442553121 in words is "thirteen trillion, one hundred twenty billion, four hundred forty-two million, five hundred fifty-three thousand, one hundred twenty-one".

Divisors: 1 19 690549608059 13120442553121