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1312100187353 is a prime number
BaseRepresentation
bin10011000101111111010…
…000111111110011011001
311122102202111222122210022
4103011333100333303121
5132444140121443403
62442434232400225
7163540031400464
oct23057720776331
94572674878708
101312100187353
1146650539302a
12192363846075
1396965c39b07
14477126062db
15241e6385d38
hex1317f43fcd9

1312100187353 has 2 divisors, whose sum is σ = 1312100187354. Its totient is φ = 1312100187352.

The previous prime is 1312100187341. The next prime is 1312100187367. The reversal of 1312100187353 is 3537810012131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 915089299609 + 397010887744 = 956603^2 + 630088^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312100187353 - 224 = 1312083410137 is a prime.

It is a super-2 number, since 2×13121001873532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1312100187373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656050093676 + 656050093677.

It is an arithmetic number, because the mean of its divisors is an integer number (656050093677).

Almost surely, 21312100187353 is an apocalyptic number.

It is an amenable number.

1312100187353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312100187353 is an equidigital number, since it uses as much as digits as its factorization.

1312100187353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 35.

Adding to 1312100187353 its reverse (3537810012131), we get a palindrome (4849910199484).

The spelling of 1312100187353 in words is "one trillion, three hundred twelve billion, one hundred million, one hundred eighty-seven thousand, three hundred fifty-three".