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131210022017 is a prime number
BaseRepresentation
bin111101000110010111…
…0100000110010000001
3110112200020210201210002
41322030232200302001
54122204231201032
6140135502045345
712323335533224
oct1721456406201
9415606721702
10131210022017
1150711700628
1221519b79855
13c4b07978a9
1464ca0875bb
15362e1cd862
hex1e8cba0c81

131210022017 has 2 divisors, whose sum is σ = 131210022018. Its totient is φ = 131210022016.

The previous prime is 131210022011. The next prime is 131210022043. The reversal of 131210022017 is 710220012131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107122671616 + 24087350401 = 327296^2 + 155201^2 .

It is a cyclic number.

It is not a de Polignac number, because 131210022017 - 228 = 130941586561 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131210022017.

It is not a weakly prime, because it can be changed into another prime (131210022011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605011008 + 65605011009.

It is an arithmetic number, because the mean of its divisors is an integer number (65605011009).

Almost surely, 2131210022017 is an apocalyptic number.

It is an amenable number.

131210022017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210022017 is an equidigital number, since it uses as much as digits as its factorization.

131210022017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

Adding to 131210022017 its reverse (710220012131), we get a palindrome (841430034148).

The spelling of 131210022017 in words is "one hundred thirty-one billion, two hundred ten million, twenty-two thousand, seventeen".