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131210083 is a prime number
BaseRepresentation
bin1111101001000…
…01101101100011
3100010220011101201
413310201231203
5232042210313
621004142031
73152160454
oct764415543
9303804351
10131210083
1168079094
1237b37917
1321250504
14135d712b
15b7bc0dd
hex7d21b63

131210083 has 2 divisors, whose sum is σ = 131210084. Its totient is φ = 131210082.

The previous prime is 131210021. The next prime is 131210087. The reversal of 131210083 is 380012131.

It is a strong prime.

It is an emirp because it is prime and its reverse (380012131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131210083 - 213 = 131201891 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131210083.

It is not a weakly prime, because it can be changed into another prime (131210087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605041 + 65605042.

It is an arithmetic number, because the mean of its divisors is an integer number (65605042).

Almost surely, 2131210083 is an apocalyptic number.

131210083 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210083 is an equidigital number, since it uses as much as digits as its factorization.

131210083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 131210083 is about 11454.6969842070. The cubic root of 131210083 is about 508.1466538270.

The spelling of 131210083 in words is "one hundred thirty-one million, two hundred ten thousand, eighty-three".