Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …100001000111101111011 |
3 | 11122102202120112112001201 |
4 | 103011333110020331323 |
5 | 132444140324330243 |
6 | 2442434302155031 |
7 | 163540041401644 |
oct | 23057724107573 |
9 | 4572676475051 |
10 | 1312101011323 |
11 | 4665058a60a3 |
12 | 192363b82a77 |
13 | 96966167b7b |
14 | 4771277c6cb |
15 | 241e649a04d |
hex | 1317f508f7b |
1312101011323 has 2 divisors, whose sum is σ = 1312101011324. Its totient is φ = 1312101011322.
The previous prime is 1312101011303. The next prime is 1312101011341. The reversal of 1312101011323 is 3231101012131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312101011323 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312101011323.
It is not a weakly prime, because it can be changed into another prime (1312101011303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656050505661 + 656050505662.
It is an arithmetic number, because the mean of its divisors is an integer number (656050505662).
Almost surely, 21312101011323 is an apocalyptic number.
1312101011323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312101011323 is an equidigital number, since it uses as much as digits as its factorization.
1312101011323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1312101011323 its reverse (3231101012131), we get a palindrome (4543202023454).
The spelling of 1312101011323 in words is "one trillion, three hundred twelve billion, one hundred one million, eleven thousand, three hundred twenty-three".
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