Search a number
-
+
13121022031009 is a prime number
BaseRepresentation
bin1011111011101111100111…
…0110110111010010100001
31201110100122120210200202021
42332323321312313102201
53204433323114443014
643523414142421441
72522651105033134
oct276737166672241
951410576720667
1013121022031009
1141a9659965942
12157ab37891881
137423cb824659
143350bcdb221b
1517b494221624
hexbeef9db74a1

13121022031009 has 2 divisors, whose sum is σ = 13121022031010. Its totient is φ = 13121022031008.

The previous prime is 13121022030971. The next prime is 13121022031021. The reversal of 13121022031009 is 90013022012131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9750181110784 + 3370840920225 = 3122528^2 + 1835985^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121022031009 is a prime.

It is a super-2 number, since 2×131210220310092 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13121022031049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560511015504 + 6560511015505.

It is an arithmetic number, because the mean of its divisors is an integer number (6560511015505).

Almost surely, 213121022031009 is an apocalyptic number.

It is an amenable number.

13121022031009 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121022031009 is an equidigital number, since it uses as much as digits as its factorization.

13121022031009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 13121022031009 in words is "thirteen trillion, one hundred twenty-one billion, twenty-two million, thirty-one thousand, nine".