Base | Representation |
---|---|
bin | 1011111011101111101001… |
… | …1001111101101001111010 |
3 | 1201110100200020010011022020 |
4 | 2332323322121331221322 |
5 | 3204433332443411442 |
6 | 43523415111535310 |
7 | 2522651246164422 |
oct | 276737231755172 |
9 | 51410606104266 |
10 | 13121031232122 |
11 | 41a966407a870 |
12 | 157ab3a98a536 |
13 | 7424006c66b8 |
14 | 3350c02c9482 |
15 | 17b494e3c9ec |
hex | beefa67da7a |
13121031232122 has 64 divisors (see below), whose sum is σ = 28657394196480. Its totient is φ = 3971948688000.
The previous prime is 13121031232109. The next prime is 13121031232129. The reversal of 13121031232122 is 22123213012131.
It is a super-2 number, since 2×131210312321222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13121031232092 and 13121031232101.
It is not an unprimeable number, because it can be changed into a prime (13121031232129) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 259022497 + ... + 259073147.
It is an arithmetic number, because the mean of its divisors is an integer number (447771784320).
Almost surely, 213121031232122 is an apocalyptic number.
13121031232122 is an abundant number, since it is smaller than the sum of its proper divisors (15536362964358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121031232122 is a wasteful number, since it uses less digits than its factorization.
13121031232122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54659.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 13121031232122 its reverse (22123213012131), we get a palindrome (35244244244253).
The spelling of 13121031232122 in words is "thirteen trillion, one hundred twenty-one billion, thirty-one million, two hundred thirty-two thousand, one hundred twenty-two".
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