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131210321113 = 1139911510687
BaseRepresentation
bin111101000110010111…
…1101001110011011001
3110112200021100221001201
41322030233221303121
54122204320233423
6140135512314201
712323341220224
oct1721457516331
9415607327051
10131210321113
1150711895313
122151a0a2961
13c4b0870a81
1464ca1245bb
15362e23c2ad
hex1e8cbe9cd9

131210321113 has 4 divisors (see below), whose sum is σ = 131221843200. Its totient is φ = 131198799028.

The previous prime is 131210321101. The next prime is 131210321129. The reversal of 131210321113 is 311123012131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131210321113 is a prime.

It is a super-2 number, since 2×1312103211132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131210321173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5743945 + ... + 5766742.

It is an arithmetic number, because the mean of its divisors is an integer number (32805460800).

Almost surely, 2131210321113 is an apocalyptic number.

It is an amenable number.

131210321113 is a deficient number, since it is larger than the sum of its proper divisors (11522087).

131210321113 is a wasteful number, since it uses less digits than its factorization.

131210321113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11522086.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 131210321113 its reverse (311123012131), we get a palindrome (442333333244).

The spelling of 131210321113 in words is "one hundred thirty-one billion, two hundred ten million, three hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 11399 11510687 131210321113