Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …100111010111010010011 |
3 | 11122102202201212110102121 |
4 | 103011333130322322103 |
5 | 132444141422004133 |
6 | 2442434423355111 |
7 | 163540100066335 |
oct | 23057734727223 |
9 | 4572681773377 |
10 | 1312103313043 |
11 | 466507128446 |
12 | 1923648b2a97 |
13 | 96966792733 |
14 | 47712bbb455 |
15 | 241e67a202d |
hex | 1317f73ae93 |
1312103313043 has 2 divisors, whose sum is σ = 1312103313044. Its totient is φ = 1312103313042.
The previous prime is 1312103312981. The next prime is 1312103313089. The reversal of 1312103313043 is 3403133012131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3403133012131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312103313043 - 213 = 1312103304851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312103312999 and 1312103313017.
It is not a weakly prime, because it can be changed into another prime (1312103323043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656051656521 + 656051656522.
It is an arithmetic number, because the mean of its divisors is an integer number (656051656522).
Almost surely, 21312103313043 is an apocalyptic number.
1312103313043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312103313043 is an equidigital number, since it uses as much as digits as its factorization.
1312103313043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1312103313043 its reverse (3403133012131), we get a palindrome (4715236325174).
The spelling of 1312103313043 in words is "one trillion, three hundred twelve billion, one hundred three million, three hundred thirteen thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •