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131210897472401 is a prime number
BaseRepresentation
bin11101110101010111101010…
…111011110011101110010001
3122012120122021001020100120012
4131311113222323303232101
5114144224404223104101
61143021242033124305
736431450233330205
oct3565275273635621
9565518231210505
10131210897472401
1138898257a6465a
12128716740b9695
13582a19977a3c6
1424588d9b08b05
15102816ad1ebbb
hex7755eaef3b91

131210897472401 has 2 divisors, whose sum is σ = 131210897472402. Its totient is φ = 131210897472400.

The previous prime is 131210897472371. The next prime is 131210897472443. The reversal of 131210897472401 is 104274798012131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128773676926801 + 2437220545600 = 11347849^2 + 1561160^2 .

It is an emirp because it is prime and its reverse (104274798012131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131210897472401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131210897472401.

It is not a weakly prime, because it can be changed into another prime (131210897472301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605448736200 + 65605448736201.

It is an arithmetic number, because the mean of its divisors is an integer number (65605448736201).

Almost surely, 2131210897472401 is an apocalyptic number.

It is an amenable number.

131210897472401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131210897472401 is an equidigital number, since it uses as much as digits as its factorization.

131210897472401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 677376, while the sum is 50.

The spelling of 131210897472401 in words is "one hundred thirty-one trillion, two hundred ten billion, eight hundred ninety-seven million, four hundred seventy-two thousand, four hundred one".