Base | Representation |
---|---|
bin | 1011111011101111111010… |
… | …0000010111110100001100 |
3 | 1201110100212000112222220121 |
4 | 2332323332200113310030 |
5 | 3204434003101133004 |
6 | 43523430010154324 |
7 | 2522653042655203 |
oct | 276737640276414 |
9 | 51410760488817 |
10 | 13121100021004 |
11 | 41a9699993988 |
12 | 157ab59a229a4 |
13 | 742411a2cb91 |
14 | 3350c94b423a |
15 | 17b49aec9854 |
hex | beefe817d0c |
13121100021004 has 24 divisors (see below), whose sum is σ = 23586158045408. Its totient is φ = 6382252465920.
The previous prime is 13121100020999. The next prime is 13121100021011. The reversal of 13121100021004 is 40012000112131.
It is a super-2 number, since 2×131211000210042 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5880504 + ... + 7798879.
Almost surely, 213121100021004 is an apocalyptic number.
It is an amenable number.
13121100021004 is a deficient number, since it is larger than the sum of its proper divisors (10465058024404).
13121100021004 is a wasteful number, since it uses less digits than its factorization.
13121100021004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13685905 (or 13685903 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 13121100021004 its reverse (40012000112131), we get a palindrome (53133100133135).
The spelling of 13121100021004 in words is "thirteen trillion, one hundred twenty-one billion, one hundred million, twenty-one thousand, four".
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