13121101101331 has 2 divisors, whose sum is σ = 13121101101332. Its totient is φ = 13121101101330.

The previous prime is 13121101101247. The next prime is 13121101101389. The reversal of 13121101101331 is 13310110112131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13121101101331 - 2⁹ = 13121101100819 is a prime.

It is a super-2 number, since 2×13121101101331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13121101101299 and 13121101101308.

It is not a weakly prime, because it can be changed into another prime (13121101101931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560550550665 + 6560550550666.

It is an arithmetic number, because the mean of its divisors is an integer number (6560550550666).

Almost surely, 2^{13121101101331} is an apocalyptic number.

13121101101331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121101101331 is an equidigital number, since it uses as much as digits as its factorization.

13121101101331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 13121101101331 its reverse (13310110112131), we get a palindrome (26431211213462).

The spelling of 13121101101331 in words is "thirteen trillion, one hundred twenty-one billion, one hundred one million, one hundred one thousand, three hundred thirty-one".