Base | Representation |
---|---|
bin | 11101110101010111110010… |
… | …010011100010010101000011 |
3 | 122012120122120122220222011221 |
4 | 131311113302103202111003 |
5 | 114144230132402224443 |
6 | 1143021302211415511 |
7 | 36431453264406121 |
oct | 3565276223422503 |
9 | 565518518828157 |
10 | 131211021133123 |
11 | 388983108467a8 |
12 | 128716a95b4597 |
13 | 582a1b9286629 |
14 | 245890c2d8911 |
15 | 1028176ae9eed |
hex | 7755f24e2543 |
131211021133123 has 2 divisors, whose sum is σ = 131211021133124. Its totient is φ = 131211021133122.
The previous prime is 131211021133067. The next prime is 131211021133151. The reversal of 131211021133123 is 321331120112131.
It is a strong prime.
It is an emirp because it is prime and its reverse (321331120112131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131211021133123 - 225 = 131210987578691 is a prime.
It is not a weakly prime, because it can be changed into another prime (131211021133523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605510566561 + 65605510566562.
It is an arithmetic number, because the mean of its divisors is an integer number (65605510566562).
Almost surely, 2131211021133123 is an apocalyptic number.
131211021133123 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211021133123 is an equidigital number, since it uses as much as digits as its factorization.
131211021133123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 131211021133123 its reverse (321331120112131), we get a palindrome (452542141245254).
The spelling of 131211021133123 in words is "one hundred thirty-one trillion, two hundred eleven billion, twenty-one million, one hundred thirty-three thousand, one hundred twenty-three".
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