13121110033 has 2 divisors, whose sum is σ = 13121110034. Its totient is φ = 13121110032.

The previous prime is 13121109977. The next prime is 13121110039. The reversal of 13121110033 is 33001112131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11396203009 + 1724907024 = 106753^2 + 41532^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121110033 - 2²⁹ = 12584239121 is a prime.

It is a super-3 number, since 3×13121110033³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13121109989 and 13121110016.

It is not a weakly prime, because it can be changed into another prime (13121110039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560555016 + 6560555017.

It is an arithmetic number, because the mean of its divisors is an integer number (6560555017).

Almost surely, 2^13121110033 is an apocalyptic number.

It is an amenable number.

13121110033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121110033 is an equidigital number, since it uses as much as digits as its factorization.

13121110033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13121110033 its reverse (33001112131), we get a palindrome (46122222164).

The spelling of 13121110033 in words is "thirteen billion, one hundred twenty-one million, one hundred ten thousand, thirty-three".