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13121121312193 is a prime number
BaseRepresentation
bin1011111011101111111111…
…0001100101110111000001
31201110100220111121200221011
42332323333301211313001
53204434024023442233
643523432050400521
72522653421642506
oct276737761456701
951410814550834
1013121121312193
1141a96aaa06304
12157ab64b90141
13742416275c0b
143350cc2574ad
1517b49ccd30cd
hexbeeffc65dc1

13121121312193 has 2 divisors, whose sum is σ = 13121121312194. Its totient is φ = 13121121312192.

The previous prime is 13121121312179. The next prime is 13121121312253. The reversal of 13121121312193 is 39121312112131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13105609107889 + 15512204304 = 3620167^2 + 124548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121121312193 is a prime.

It is not a weakly prime, because it can be changed into another prime (13121121312113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560560656096 + 6560560656097.

It is an arithmetic number, because the mean of its divisors is an integer number (6560560656097).

Almost surely, 213121121312193 is an apocalyptic number.

It is an amenable number.

13121121312193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121121312193 is an equidigital number, since it uses as much as digits as its factorization.

13121121312193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1944, while the sum is 31.

The spelling of 13121121312193 in words is "thirteen trillion, one hundred twenty-one billion, one hundred twenty-one million, three hundred twelve thousand, one hundred ninety-three".