Base | Representation |
---|---|
bin | 11101110101011000001010… |
… | …111011110011010000011001 |
3 | 122012120200122110110010101020 |
4 | 131311120022323303100121 |
5 | 114144232004142411101 |
6 | 1143021411212113053 |
7 | 36431466442542021 |
oct | 3565301273632031 |
9 | 565520573403336 |
10 | 131211434341401 |
11 | 38898503013247 |
12 | 128717a3a65789 |
13 | 582a253a70b7b |
14 | 245894b13aa81 |
15 | 102819d01c136 |
hex | 77560aef3419 |
131211434341401 has 8 divisors (see below), whose sum is σ = 180981288746880. Its totient is φ = 84457934748432.
The previous prime is 131211434341387. The next prime is 131211434341501. The reversal of 131211434341401 is 104143434112131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131211434341401 - 229 = 131210897470489 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131211434341201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 754088703025 + ... + 754088703198.
It is an arithmetic number, because the mean of its divisors is an integer number (22622661093360).
Almost surely, 2131211434341401 is an apocalyptic number.
It is an amenable number.
131211434341401 is a deficient number, since it is larger than the sum of its proper divisors (49769854405479).
131211434341401 is a wasteful number, since it uses less digits than its factorization.
131211434341401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1508177406255.
The product of its (nonzero) digits is 13824, while the sum is 33.
Adding to 131211434341401 its reverse (104143434112131), we get a palindrome (235354868453532).
The spelling of 131211434341401 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred thirty-four million, three hundred forty-one thousand, four hundred one".
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