Base | Representation |
---|---|
bin | 11101110101011000001010… |
… | …111011110011101111010001 |
3 | 122012120200122110110020002102 |
4 | 131311120022323303233101 |
5 | 114144232004142442002 |
6 | 1143021411212130145 |
7 | 36431466442550543 |
oct | 3565301273635721 |
9 | 565520573406072 |
10 | 131211434343377 |
11 | 38898503014783 |
12 | 128717a3a66955 |
13 | 582a253a71a3b |
14 | 245894b13b693 |
15 | 102819d01ca02 |
hex | 77560aef3bd1 |
131211434343377 has 2 divisors, whose sum is σ = 131211434343378. Its totient is φ = 131211434343376.
The previous prime is 131211434343271. The next prime is 131211434343391. The reversal of 131211434343377 is 773343434112131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127227593989441 + 3983840353936 = 11279521^2 + 1995956^2 .
It is a cyclic number.
It is not a de Polignac number, because 131211434343377 - 222 = 131211430149073 is a prime.
It is not a weakly prime, because it can be changed into another prime (131211434348377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605717171688 + 65605717171689.
It is an arithmetic number, because the mean of its divisors is an integer number (65605717171689).
Almost surely, 2131211434343377 is an apocalyptic number.
It is an amenable number.
131211434343377 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211434343377 is an equidigital number, since it uses as much as digits as its factorization.
131211434343377 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1524096, while the sum is 47.
The spelling of 131211434343377 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred thirty-four million, three hundred forty-three thousand, three hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.286 sec. • engine limits •