Base | Representation |
---|---|
bin | 1011111011110000000100… |
… | …1000111100001011000001 |
3 | 1201110100222002201000222021 |
4 | 2332330001020330023001 |
5 | 3204434100404210423 |
6 | 43523434225241441 |
7 | 2522654120401342 |
oct | 276740110741301 |
9 | 51410862630867 |
10 | 13121144210113 |
11 | 41a9711925905 |
12 | 157ab70793281 |
13 | 74241ac32394 |
14 | 3350d12d80c9 |
15 | 17b49ed0795d |
hex | bef0123c2c1 |
13121144210113 has 2 divisors, whose sum is σ = 13121144210114. Its totient is φ = 13121144210112.
The previous prime is 13121144210077. The next prime is 13121144210117. The reversal of 13121144210113 is 31101244112131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9820501877824 + 3300642332289 = 3133768^2 + 1816767^2 .
It is a cyclic number.
It is not a de Polignac number, because 13121144210113 - 217 = 13121144079041 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121144210117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560572105056 + 6560572105057.
It is an arithmetic number, because the mean of its divisors is an integer number (6560572105057).
Almost surely, 213121144210113 is an apocalyptic number.
It is an amenable number.
13121144210113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121144210113 is an equidigital number, since it uses as much as digits as its factorization.
13121144210113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13121144210113 its reverse (31101244112131), we get a palindrome (44222388322244).
The spelling of 13121144210113 in words is "thirteen trillion, one hundred twenty-one billion, one hundred forty-four million, two hundred ten thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.121 sec. • engine limits •