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13121144210113 is a prime number
BaseRepresentation
bin1011111011110000000100…
…1000111100001011000001
31201110100222002201000222021
42332330001020330023001
53204434100404210423
643523434225241441
72522654120401342
oct276740110741301
951410862630867
1013121144210113
1141a9711925905
12157ab70793281
1374241ac32394
143350d12d80c9
1517b49ed0795d
hexbef0123c2c1

13121144210113 has 2 divisors, whose sum is σ = 13121144210114. Its totient is φ = 13121144210112.

The previous prime is 13121144210077. The next prime is 13121144210117. The reversal of 13121144210113 is 31101244112131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9820501877824 + 3300642332289 = 3133768^2 + 1816767^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121144210113 - 217 = 13121144079041 is a prime.

It is not a weakly prime, because it can be changed into another prime (13121144210117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560572105056 + 6560572105057.

It is an arithmetic number, because the mean of its divisors is an integer number (6560572105057).

Almost surely, 213121144210113 is an apocalyptic number.

It is an amenable number.

13121144210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121144210113 is an equidigital number, since it uses as much as digits as its factorization.

13121144210113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13121144210113 its reverse (31101244112131), we get a palindrome (44222388322244).

The spelling of 13121144210113 in words is "thirteen trillion, one hundred twenty-one billion, one hundred forty-four million, two hundred ten thousand, one hundred thirteen".