Base | Representation |
---|---|
bin | 10011000110000000011… |
… | …101011011010111001001 |
3 | 11122102210220200120202212 |
4 | 103012000131123113021 |
5 | 132444210234120202 |
6 | 2442440230034505 |
7 | 163540363606121 |
oct | 23060035332711 |
9 | 4572726616685 |
10 | 1312120223177 |
11 | 466515728265 |
12 | 19236a4a8a35 |
13 | 9696a13362a |
14 | 4771513dc81 |
15 | 241e7ee2652 |
hex | 1318075b5c9 |
1312120223177 has 2 divisors, whose sum is σ = 1312120223178. Its totient is φ = 1312120223176.
The previous prime is 1312120223093. The next prime is 1312120223189. The reversal of 1312120223177 is 7713220212131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 990972466576 + 321147756601 = 995476^2 + 566699^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312120223177 - 216 = 1312120157641 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312120213177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656060111588 + 656060111589.
It is an arithmetic number, because the mean of its divisors is an integer number (656060111589).
Almost surely, 21312120223177 is an apocalyptic number.
It is an amenable number.
1312120223177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312120223177 is an equidigital number, since it uses as much as digits as its factorization.
1312120223177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7056, while the sum is 32.
The spelling of 1312120223177 in words is "one trillion, three hundred twelve billion, one hundred twenty million, two hundred twenty-three thousand, one hundred seventy-seven".
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