Base | Representation |
---|---|
bin | 10011000110000000100… |
… | …100010010100011010001 |
3 | 11122102211001001222102112 |
4 | 103012000210102203101 |
5 | 132444211214201342 |
6 | 2442440332355105 |
7 | 163540415110565 |
oct | 23060044224321 |
9 | 4572731058375 |
10 | 1312122022097 |
11 | 466516746877 |
12 | 19236b015a95 |
13 | 9696a613393 |
14 | 4771548b6a5 |
15 | 241e824a682 |
hex | 131809128d1 |
1312122022097 has 2 divisors, whose sum is σ = 1312122022098. Its totient is φ = 1312122022096.
The previous prime is 1312122022093. The next prime is 1312122022111. The reversal of 1312122022097 is 7902202212131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 760661321281 + 551460700816 = 872159^2 + 742604^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312122022097 - 22 = 1312122022093 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312122022093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656061011048 + 656061011049.
It is an arithmetic number, because the mean of its divisors is an integer number (656061011049).
Almost surely, 21312122022097 is an apocalyptic number.
It is an amenable number.
1312122022097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312122022097 is an equidigital number, since it uses as much as digits as its factorization.
1312122022097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
The spelling of 1312122022097 in words is "one trillion, three hundred twelve billion, one hundred twenty-two million, twenty-two thousand, ninety-seven".
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