Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …011011100111000101010011 |
3 | 122012120202122211022211121201 |
4 | 131311120321123213011103 |
5 | 114144240103343311313 |
6 | 1143022020440132031 |
7 | 36431524664314621 |
oct | 3565307133470523 |
9 | 565522584284551 |
10 | 131212214432083 |
11 | 38898873395994 |
12 | 12871981167017 |
13 | 582a3495729a5 |
14 | 24589c29a2511 |
15 | 10281e67600dd |
hex | 7756396e7153 |
131212214432083 has 2 divisors, whose sum is σ = 131212214432084. Its totient is φ = 131212214432082.
The previous prime is 131212214432077. The next prime is 131212214432207. The reversal of 131212214432083 is 380234412212131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131212214432083 - 217 = 131212214301011 is a prime.
It is not a weakly prime, because it can be changed into another prime (131212214432053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606107216041 + 65606107216042.
It is an arithmetic number, because the mean of its divisors is an integer number (65606107216042).
Almost surely, 2131212214432083 is an apocalyptic number.
131212214432083 is a deficient number, since it is larger than the sum of its proper divisors (1).
131212214432083 is an equidigital number, since it uses as much as digits as its factorization.
131212214432083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 37.
The spelling of 131212214432083 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred fourteen million, four hundred thirty-two thousand, eighty-three".
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