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131212242101401 is a prime number
BaseRepresentation
bin11101110101011000111011…
…000101001010010010011001
3122012120202201202101120210021
4131311120323011022102121
5114144240132434221101
61143022023305150441
736431525451435316
oct3565307305122231
9565522652346707
10131212242101401
1138898887a7429a
121287198a48b421
13582a35220cb76
1424589c6525d0d
1510281e8dc85a1
hex77563b14a499

131212242101401 has 2 divisors, whose sum is σ = 131212242101402. Its totient is φ = 131212242101400.

The previous prime is 131212242101371. The next prime is 131212242101483. The reversal of 131212242101401 is 104101242212131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74065370303376 + 57146871798025 = 8606124^2 + 7559555^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131212242101401 is a prime.

It is a super-2 number, since 2×1312122421014012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131212242101491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606121050700 + 65606121050701.

It is an arithmetic number, because the mean of its divisors is an integer number (65606121050701).

Almost surely, 2131212242101401 is an apocalyptic number.

It is an amenable number.

131212242101401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212242101401 is an equidigital number, since it uses as much as digits as its factorization.

131212242101401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 131212242101401 its reverse (104101242212131), we get a palindrome (235313484313532).

The spelling of 131212242101401 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred forty-two million, one hundred one thousand, four hundred one".