Base | Representation |
---|---|
bin | 11101110101011000111110… |
… | …101010000101100101011010 |
3 | 122012120202212221022111101022 |
4 | 131311120332222011211122 |
5 | 114144240243320104424 |
6 | 1143022033251322442 |
7 | 36431530110511505 |
oct | 3565307652054532 |
9 | 565522787274338 |
10 | 131212302113114 |
11 | 38898908932a52 |
12 | 128719a65b0422 |
13 | 582a361792261 |
14 | 24589d04a813c |
15 | 10281ee2ce95e |
hex | 77563ea8595a |
131212302113114 has 4 divisors (see below), whose sum is σ = 196818453169674. Its totient is φ = 65606151056556.
The previous prime is 131212302113111. The next prime is 131212302113159. The reversal of 131212302113114 is 411311203212131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 94243652478889 + 36968649634225 = 9707917^2 + 6080185^2 .
It is not an unprimeable number, because it can be changed into a prime (131212302113111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32803075528277 + ... + 32803075528280.
Almost surely, 2131212302113114 is an apocalyptic number.
131212302113114 is a deficient number, since it is larger than the sum of its proper divisors (65606151056560).
131212302113114 is an equidigital number, since it uses as much as digits as its factorization.
131212302113114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65606151056559.
The product of its (nonzero) digits is 864, while the sum is 26.
Adding to 131212302113114 its reverse (411311203212131), we get a palindrome (542523505325245).
The spelling of 131212302113114 in words is "one hundred thirty-one trillion, two hundred twelve billion, three hundred two million, one hundred thirteen thousand, one hundred fourteen".
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