Base | Representation |
---|---|
bin | 1011111011110000011011… |
… | …1011110001110010100010 |
3 | 1201110101012212121221222221 |
4 | 2332330012323301302202 |
5 | 3204434300301014020 |
6 | 43523452021021254 |
7 | 2522656410605020 |
oct | 276740673616242 |
9 | 51411185557887 |
10 | 13121241423010 |
11 | 41a9761793346 |
12 | 157ab9925482a |
13 | 74243510b3c6 |
14 | 3351001a1710 |
15 | 17b4a860b6aa |
hex | bef06ef1ca2 |
13121241423010 has 64 divisors (see below), whose sum is σ = 28103905234944. Its totient is φ = 4317036019200.
The previous prime is 13121241423001. The next prime is 13121241423049. The reversal of 13121241423010 is 1032414212131.
It is a super-3 number, since 3×131212414230103 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37299202 + ... + 37649341.
It is an arithmetic number, because the mean of its divisors is an integer number (439123519296).
Almost surely, 213121241423010 is an apocalyptic number.
13121241423010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13121241423010 is an abundant number, since it is smaller than the sum of its proper divisors (14982663811934).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121241423010 is a wasteful number, since it uses less digits than its factorization.
13121241423010 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74948659.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13121241423010 its reverse (1032414212131), we get a palindrome (14153655635141).
The spelling of 13121241423010 in words is "thirteen trillion, one hundred twenty-one billion, two hundred forty-one million, four hundred twenty-three thousand, ten".
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