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131213011103401 is a prime number
BaseRepresentation
bin11101110101011001101000…
…111010101010111010101001
3122012120211201100101221012211
4131311121220322222322221
5114144243221320302101
61143022231455405121
736431553510025543
oct3565315072527251
9565524640357184
10131213011103401
1138899142062937
1212871b63b237a1
13582a44562b736
142458a5a702693
15102824167ac51
hex775668eaaea9

131213011103401 has 2 divisors, whose sum is σ = 131213011103402. Its totient is φ = 131213011103400.

The previous prime is 131213011103329. The next prime is 131213011103411. The reversal of 131213011103401 is 104301110312131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120661876544400 + 10551134559001 = 10984620^2 + 3248251^2 .

It is a cyclic number.

It is not a de Polignac number, because 131213011103401 - 243 = 122416918081193 is a prime.

It is a super-2 number, since 2×1312130111034012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131213011103411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606505551700 + 65606505551701.

It is an arithmetic number, because the mean of its divisors is an integer number (65606505551701).

Almost surely, 2131213011103401 is an apocalyptic number.

It is an amenable number.

131213011103401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131213011103401 is an equidigital number, since it uses as much as digits as its factorization.

131213011103401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 131213011103401 its reverse (104301110312131), we get a palindrome (235514121415532).

The spelling of 131213011103401 in words is "one hundred thirty-one trillion, two hundred thirteen billion, eleven million, one hundred three thousand, four hundred one".