Base | Representation |
---|---|
bin | 10011000110000001000… |
… | …111010110011101001100 |
3 | 11122102211200100221011020 |
4 | 103012001013112131030 |
5 | 132444221042310012 |
6 | 2442441301354140 |
7 | 163540556200605 |
oct | 23060107263514 |
9 | 4572750327136 |
10 | 1312131213132 |
11 | 466520954173 |
12 | 192372108950 |
13 | 9696c4b096c |
14 | 477167a0dac |
15 | 241e8e63a8c |
hex | 131811d674c |
1312131213132 has 24 divisors (see below), whose sum is σ = 3068280810672. Its totient is φ = 436428312000.
The previous prime is 1312131213131. The next prime is 1312131213191. The reversal of 1312131213132 is 2313121312131.
It is a nude number because it is divisible by every one of its digits.
It is not an unprimeable number, because it can be changed into a prime (1312131213131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118589119 + ... + 118600182.
It is an arithmetic number, because the mean of its divisors is an integer number (127845033778).
Almost surely, 21312131213132 is an apocalyptic number.
1312131213132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1312131213132 is an abundant number, since it is smaller than the sum of its proper divisors (1756149597540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312131213132 is a wasteful number, since it uses less digits than its factorization.
1312131213132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237189769 (or 237189767 counting only the distinct ones).
The product of its digits is 648, while the sum is 24.
Adding to 1312131213132 its reverse (2313121312131), we get a palindrome (3625252525263).
The spelling of 1312131213132 in words is "one trillion, three hundred twelve billion, one hundred thirty-one million, two hundred thirteen thousand, one hundred thirty-two".
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