Base | Representation |
---|---|
bin | 11101110101011001110000… |
… | …000001011101000001010011 |
3 | 122012120212000122201212101121 |
4 | 131311121300001131001103 |
5 | 114144243442330301003 |
6 | 1143022251354543111 |
7 | 36431556455253622 |
oct | 3565316001350123 |
9 | 565525018655347 |
10 | 131213130322003 |
11 | 388991a3390604 |
12 | 12871b97a37a97 |
13 | 582a464240aa2 |
14 | 2458a6c4976b9 |
15 | 102824bd79cbd |
hex | 77567005d053 |
131213130322003 has 2 divisors, whose sum is σ = 131213130322004. Its totient is φ = 131213130322002.
The previous prime is 131213130321967. The next prime is 131213130322117. The reversal of 131213130322003 is 300223031312131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131213130322003 - 233 = 131204540387411 is a prime.
It is not a weakly prime, because it can be changed into another prime (131213131322003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606565161001 + 65606565161002.
It is an arithmetic number, because the mean of its divisors is an integer number (65606565161002).
Almost surely, 2131213130322003 is an apocalyptic number.
131213130322003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131213130322003 is an equidigital number, since it uses as much as digits as its factorization.
131213130322003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 131213130322003 its reverse (300223031312131), we get a palindrome (431436161634134).
The spelling of 131213130322003 in words is "one hundred thirty-one trillion, two hundred thirteen billion, one hundred thirty million, three hundred twenty-two thousand, three".
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