Base | Representation |
---|---|
bin | 111101000110011101… |
… | …0101000011011101011 |
3 | 110112200110210010220012 |
4 | 1322030322220123223 |
5 | 4122211034332313 |
6 | 140140054122135 |
7 | 12323404534631 |
oct | 1721472503353 |
9 | 415613703805 |
10 | 131213199083 |
11 | 507134805aa |
12 | 2151b05034b |
13 | c4b133aa05 |
14 | 64ca673351 |
15 | 362e609da8 |
hex | 1e8cea86eb |
131213199083 has 2 divisors, whose sum is σ = 131213199084. Its totient is φ = 131213199082.
The previous prime is 131213199079. The next prime is 131213199097. The reversal of 131213199083 is 380991312131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131213199083 - 22 = 131213199079 is a prime.
It is a super-2 number, since 2×1312131990832 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131213199083.
It is not a weakly prime, because it can be changed into another prime (131213199883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606599541 + 65606599542.
It is an arithmetic number, because the mean of its divisors is an integer number (65606599542).
Almost surely, 2131213199083 is an apocalyptic number.
131213199083 is a deficient number, since it is larger than the sum of its proper divisors (1).
131213199083 is an equidigital number, since it uses as much as digits as its factorization.
131213199083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 131213199083 in words is "one hundred thirty-one billion, two hundred thirteen million, one hundred ninety-nine thousand, eighty-three".
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