131213234230433 has 4 divisors (see below), whose sum is σ = 131262581068080. Its totient is φ = 131163887392788.

The previous prime is 131213234230409. The next prime is 131213234230447. The reversal of 131213234230433 is 334032432312131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131213234230433 - 2¹⁰ = 131213234229409 is a prime.

It is a super-3 number, since 3×131213234230433³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131213234230393 and 131213234230402.

It is not an unprimeable number, because it can be changed into a prime (131213234238433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24673414835 + ... + 24673420152.

It is an arithmetic number, because the mean of its divisors is an integer number (32815645267020).

Almost surely, 2^{131213234230433} is an apocalyptic number.

It is an amenable number.

131213234230433 is a deficient number, since it is larger than the sum of its proper divisors (49346837647).

131213234230433 is an equidigital number, since it uses as much as digits as its factorization.

131213234230433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49346837646.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 131213234230433 its reverse (334032432312131), we get a palindrome (465245666542564).

The spelling of 131213234230433 in words is "one hundred thirty-one trillion, two hundred thirteen billion, two hundred thirty-four million, two hundred thirty thousand, four hundred thirty-three".