Base | Representation |
---|---|
bin | 10011000110000001001… |
… | …111010110111001111011 |
3 | 11122102211211022120102122 |
4 | 103012001033112321323 |
5 | 132444222111441443 |
6 | 2442441414351455 |
7 | 163540613062244 |
oct | 23060117267173 |
9 | 4572754276378 |
10 | 1312133312123 |
11 | 466522058177 |
12 | 19237295b58b |
13 | 9696ca6717a |
14 | 47716b89ccb |
15 | 241e922a968 |
hex | 131813d6e7b |
1312133312123 has 2 divisors, whose sum is σ = 1312133312124. Its totient is φ = 1312133312122.
The previous prime is 1312133312071. The next prime is 1312133312131. The reversal of 1312133312123 is 3212133312131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3212133312131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312133312123 - 216 = 1312133246587 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312133312092 and 1312133312101.
It is not a weakly prime, because it can be changed into another prime (1312133312423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656066656061 + 656066656062.
It is an arithmetic number, because the mean of its divisors is an integer number (656066656062).
Almost surely, 21312133312123 is an apocalyptic number.
1312133312123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312133312123 is an equidigital number, since it uses as much as digits as its factorization.
1312133312123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944, while the sum is 26.
Adding to 1312133312123 its reverse (3212133312131), we get a palindrome (4524266624254).
The spelling of 1312133312123 in words is "one trillion, three hundred twelve billion, one hundred thirty-three million, three hundred twelve thousand, one hundred twenty-three".
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