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1312135147 is a prime number
BaseRepresentation
bin100111000110101…
…1001011111101011
310101110000101001001
41032031121133223
510141401311042
6334111335431
744341651621
oct11615313753
93343011031
101312135147
11613736614
12307521577
1317bac663b
14c639d511
157a2dabb7
hex4e3597eb

1312135147 has 2 divisors, whose sum is σ = 1312135148. Its totient is φ = 1312135146.

The previous prime is 1312135127. The next prime is 1312135159. The reversal of 1312135147 is 7415312131.

It is a strong prime.

It is an emirp because it is prime and its reverse (7415312131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312135147 - 211 = 1312133099 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312135127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656067573 + 656067574.

It is an arithmetic number, because the mean of its divisors is an integer number (656067574).

Almost surely, 21312135147 is an apocalyptic number.

1312135147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312135147 is an equidigital number, since it uses as much as digits as its factorization.

1312135147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2520, while the sum is 28.

The square root of 1312135147 is about 36223.4060656918. The cubic root of 1312135147 is about 1094.7783228271.

Adding to 1312135147 its reverse (7415312131), we get a palindrome (8727447278).

The spelling of 1312135147 in words is "one billion, three hundred twelve million, one hundred thirty-five thousand, one hundred forty-seven".