131214000000033 has 16 divisors (see below), whose sum is σ = 194395716279360. Its totient is φ = 87473927674368.

The previous prime is 131214000000023. The next prime is 131214000000037. The reversal of 131214000000033 is 330000000412131.

It is not a de Polignac number, because 131214000000033 - 2¹⁷ = 131213999868961 is a prime.

It is a super-2 number, since 2×131214000000033² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131213999999952 and 131214000000015.

It is not an unprimeable number, because it can be changed into a prime (131214000000037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56403360 + ... + 58683617.

It is an arithmetic number, because the mean of its divisors is an integer number (12149732267460).

Almost surely, 2^{131214000000033} is an apocalyptic number.

It is an amenable number.

131214000000033 is a deficient number, since it is larger than the sum of its proper divisors (63181716279327).

131214000000033 is a wasteful number, since it uses less digits than its factorization.

131214000000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115129213 (or 115129207 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 131214000000033 its reverse (330000000412131), we get a palindrome (461214000412164).

The spelling of 131214000000033 in words is "one hundred thirty-one trillion, two hundred fourteen billion, thirty-three", and thus it is an aban number.