Base | Representation |
---|---|
bin | 1011111011110001000011… |
… | …1110110111010010101111 |
3 | 1201110101122121211202211121 |
4 | 2332330100332313102233 |
5 | 3204440121430113033 |
6 | 43523520442201411 |
7 | 2522663525534140 |
oct | 276742076672257 |
9 | 51411577752747 |
10 | 13121410004143 |
11 | 41a98389668a1 |
12 | 157b0257b3267 |
13 | 74246101495c |
14 | 335118725ac7 |
15 | 17b4b830b62d |
hex | bef10fb74af |
13121410004143 has 16 divisors (see below), whose sum is σ = 15210242596864. Its totient is φ = 11087291910240.
The previous prime is 13121410004119. The next prime is 13121410004149. The reversal of 13121410004143 is 34140001412131.
It is a de Polignac number, because none of the positive numbers 2k-13121410004143 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121410004149) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46865973 + ... + 47145118.
It is an arithmetic number, because the mean of its divisors is an integer number (950640162304).
Almost surely, 213121410004143 is an apocalyptic number.
13121410004143 is a deficient number, since it is larger than the sum of its proper divisors (2088832592721).
13121410004143 is a wasteful number, since it uses less digits than its factorization.
13121410004143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94011382.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13121410004143 its reverse (34140001412131), we get a palindrome (47261411416274).
The spelling of 13121410004143 in words is "thirteen trillion, one hundred twenty-one billion, four hundred ten million, four thousand, one hundred forty-three".
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