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13121420212001 is a prime number
BaseRepresentation
bin1011111011110001000110…
…0101110011011100100001
31201110101200100001101101102
42332330101211303130201
53204440132033241001
643523521445044145
72522664011360513
oct276742145633441
951411610041342
1013121420212001
1141a98436a9142
12157b0290b6655
13742463179cca
14335119c21bb3
1517b4b9175e6b
hexbef11973721

13121420212001 has 2 divisors, whose sum is σ = 13121420212002. Its totient is φ = 13121420212000.

The previous prime is 13121420211983. The next prime is 13121420212013. The reversal of 13121420212001 is 10021202412131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7942245603601 + 5179174608400 = 2818199^2 + 2275780^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121420212001 is a prime.

It is not a weakly prime, because it can be changed into another prime (13121420212031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560710106000 + 6560710106001.

It is an arithmetic number, because the mean of its divisors is an integer number (6560710106001).

Almost surely, 213121420212001 is an apocalyptic number.

It is an amenable number.

13121420212001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121420212001 is an equidigital number, since it uses as much as digits as its factorization.

13121420212001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13121420212001 its reverse (10021202412131), we get a palindrome (23142622624132).

The spelling of 13121420212001 in words is "thirteen trillion, one hundred twenty-one billion, four hundred twenty million, two hundred twelve thousand, one".