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131214310834 = 2286492290033
BaseRepresentation
bin111101000110011111…
…0110111110110110010
3110112200112212121221011
41322030332313312302
54122211330421314
6140140134021134
712323420145115
oct1721476676662
9415615777834
10131214310834
115071406a902
122151b4a77aa
13c4b1639a59
1464ca88257c
15362e7794c4
hex1e8cfb7db2

131214310834 has 8 divisors (see below), whose sum is σ = 196828422300. Its totient is φ = 65604836736.

The previous prime is 131214310819. The next prime is 131214310873. The reversal of 131214310834 is 438013412131.

It can be written as a sum of positive squares in 2 ways, for example, as 130575990609 + 638320225 = 361353^2 + 25265^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-5 number, since 5×1312143108345 (a number of 57 digits) contains 55555 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131214310796 and 131214310805.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1087719 + ... + 1202314.

Almost surely, 2131214310834 is an apocalyptic number.

131214310834 is a deficient number, since it is larger than the sum of its proper divisors (65614111466).

131214310834 is a wasteful number, since it uses less digits than its factorization.

131214310834 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2318684.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 131214310834 its reverse (438013412131), we get a palindrome (569227722965).

The spelling of 131214310834 in words is "one hundred thirty-one billion, two hundred fourteen million, three hundred ten thousand, eight hundred thirty-four".

Divisors: 1 2 28649 57298 2290033 4580066 65607155417 131214310834