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131221122429689 is a prime number
BaseRepresentation
bin11101110101100001001100…
…011000111011001011111001
3122012121121122122022000001222
4131311201030120323023321
5114144411324320222224
61143030052413321425
736432261512123255
oct3565411430731371
9565547578260058
10131221122429689
11388a1624758386
1212873648496275
13582b138c4c7a6
1424591c9aa9265
151028568816b5e
hex77584c63b2f9

131221122429689 has 2 divisors, whose sum is σ = 131221122429690. Its totient is φ = 131221122429688.

The previous prime is 131221122429671. The next prime is 131221122429701. The reversal of 131221122429689 is 986924221122131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129767024090089 + 1454098339600 = 11391533^2 + 1205860^2 .

It is a cyclic number.

It is not a de Polignac number, because 131221122429689 - 228 = 131220853994233 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131221122429689.

It is not a weakly prime, because it can be changed into another prime (131221122429289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610561214844 + 65610561214845.

It is an arithmetic number, because the mean of its divisors is an integer number (65610561214845).

Almost surely, 2131221122429689 is an apocalyptic number.

It is an amenable number.

131221122429689 is a deficient number, since it is larger than the sum of its proper divisors (1).

131221122429689 is an equidigital number, since it uses as much as digits as its factorization.

131221122429689 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1492992, while the sum is 53.

The spelling of 131221122429689 in words is "one hundred thirty-one trillion, two hundred twenty-one billion, one hundred twenty-two million, four hundred twenty-nine thousand, six hundred eighty-nine".